Leetcode 2441. Largest Positive Integer That Exists With It's Negative
I am a developer from Nashville, TN. I specialize in the .NET tech stack. I have created many projects in Blazor WASM, Xamarin, MAUI, etc.
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I am a developer from Nashville, TN. I specialize in the .NET tech stack. I have created many projects in Blazor WASM, Xamarin, MAUI, etc.
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A series documenting my journey to improving my ability to solve LeetCode problems through YouTube videos, study plans, articles, etc. Using my own words for later reference.
Intuition Find position of ch (if any) then use two pointers to swap characters until string is reveresed from beginning to index of ch Approach Start by checking each character for ch. If we find it, that's where our right pointer will start. Our le...
Intuition Get the length of the subsequence (if any) and subtract it from the length of t to find out how many characters we have to append (if any) Approach Keep a count of the length of the subsequence while iterating through s and then subtract th...
Intuition Find position of ch (if any) then use two pointers to swap characters until string is reveresed from beginning to index of ch Approach Start by checking each character for ch. If we find it, that's where our right pointer will start. Our le...
Intuition Use two pointers to iterate through the string checking each adjacent character to see if it is "bad" or "good". Approach First if the string is 1 or fewer characters we know it is good so we can just return it. If that's not the case, we c...
Intuition Since both arrays are sorted, we can find the minimum common value by iterating from left to right with two pointers. Approach Initialize both pointers to 0 to start at the beginning of the array. While both pointers are within bounds of th...
Sort the array and check if the start and end of the array match. If not, increment or decrement accordingly.
First sort the array. Then use two pointers. One at the beginning, the other at the end. Check to see if the value at the beginning (the smallest integer) is the same as the value at the end (the highest integer) once converted from negative to positive.
If it's the same, return that value.
If the converted integer is smaller, decrement the right pointer.
If the converted integer is larger, increment the left pointer.
If the left and right pointers meet, there is no matching value so return -1.
public class Solution
{
public int FindMaxK(int[] nums)
{
Array.Sort(nums);
int left = 0;
int right = nums.Length - 1;
while(left < right)
{
var comparer = nums[left] * -1;
if(comparer == nums[right])
{
return comparer;
}
else if(comparer < nums[right])
{
right--;
}
else
{
left++;
}
}
return -1;
}
}